0=-16t^2+12t+1400

Solution for 0=-16t^2+12t+1400 equation:

0=-16t^2+12t+1400

We move all terms to the left:

0-(-16t^2+12t+1400)=0

We add all the numbers together, and all the variables

-(-16t^2+12t+1400)=0

We get rid of parentheses

16t^2-12t-1400=0

a = 16; b = -12; c = -1400;
Δ = b2-4ac
Δ = -122-4·16·(-1400)
Δ = 89744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{89744}=\sqrt{16*5609}=\sqrt{16}*\sqrt{5609}=4\sqrt{5609}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{5609}}{2*16}=\frac{12-4\sqrt{5609}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{5609}}{2*16}=\frac{12+4\sqrt{5609}}{32}
$